jax.tree_util.tree_leaves_with_path#

jax.tree_util.tree_leaves_with_path(tree, is_leaf=None, is_leaf_takes_path=False)[source]#

的别名 jax.tree.leaves_with_path()

参数:
  • tree (Any)

  • is_leaf (Callable[..., bool] | None)

  • is_leaf_takes_path (bool)

返回类型:

list[tuple[KeyPath, Any]]